Wednesday, February 5, 2014

Chemistry

Enzyme lab questions 1. How do you account for the differences in rates? 1. In the first taste, 2 mL of H2O2 was mixed with 0.1g sand. In this mixture, on that point atomic number 18 no enzymes present and because no products are yeared. The reply rate was rated 0, just as we anticipated. 2. The 2nd test was a mixture of 2 mL H2O2 and 0.1g manganese dioxide. We prat use the same principal we used for the first experiment, manganese dioxide is not a protein, not an enzyme, it is a catalyst. Due to this, no products are boded, and just as we anticipated, the reception rate was stipulation a 0. 3. The 3rd experiment is a mixture of 2 mL H2O2 and colored. In this situation, both the substrate (H2O2) and the enzyme (catalase) are present, and therefrom the products, irrigate and oxygen are produced. Just as our boniface anticipated, the response rate would be fairly high, and by our observations, we gave the reply rate a 3. 4. The 4th mixture is composed of 2 mL H2O2 and a small portion of a potato. I anticipated that there would be a response, however, I knew that the reaction rate would not be as high as the liver because the enzyme concentration in a potato should be lower than that of the liver. Through our observations, this experiment received a 2. 5. The twenty percent experiment contains liquid from experiment 3, the left everyplace liver from experiment 3 and a fresh piece of liver. The reaction rate should be 0 because in the left everywhere liquid from experiment 3, there are only products and no substrates (this is because the enzyme in experiment 3 has already formed the products urine and oxygen from the H2O2). The new liver has enzymes, however, because there are no substrates, there can be no reaction to form products. From our observations, we gave the reaction rate a 0, like we anticipated. 6. Experiment 6 is a combination of left over liquid from experiment 3, liver used in expe riment 3 and 1 mL H2O2. This experiment was ! done to show that enzymes may be reused...If you want to get a full essay, order it on our website: BestEssayCheap.com

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